Integrand size = 16, antiderivative size = 75 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {a^3 A}{9 x^9}-\frac {a^2 (3 A b+a B)}{8 x^8}-\frac {3 a b (A b+a B)}{7 x^7}-\frac {b^2 (A b+3 a B)}{6 x^6}-\frac {b^3 B}{5 x^5} \]
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Time = 0.02 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.062, Rules used = {77} \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {a^3 A}{9 x^9}-\frac {a^2 (a B+3 A b)}{8 x^8}-\frac {b^2 (3 a B+A b)}{6 x^6}-\frac {3 a b (a B+A b)}{7 x^7}-\frac {b^3 B}{5 x^5} \]
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Rule 77
Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {a^3 A}{x^{10}}+\frac {a^2 (3 A b+a B)}{x^9}+\frac {3 a b (A b+a B)}{x^8}+\frac {b^2 (A b+3 a B)}{x^7}+\frac {b^3 B}{x^6}\right ) \, dx \\ & = -\frac {a^3 A}{9 x^9}-\frac {a^2 (3 A b+a B)}{8 x^8}-\frac {3 a b (A b+a B)}{7 x^7}-\frac {b^2 (A b+3 a B)}{6 x^6}-\frac {b^3 B}{5 x^5} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.92 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {84 b^3 x^3 (5 A+6 B x)+180 a b^2 x^2 (6 A+7 B x)+135 a^2 b x (7 A+8 B x)+35 a^3 (8 A+9 B x)}{2520 x^9} \]
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Time = 0.39 (sec) , antiderivative size = 66, normalized size of antiderivative = 0.88
method | result | size |
default | \(-\frac {a^{3} A}{9 x^{9}}-\frac {a^{2} \left (3 A b +B a \right )}{8 x^{8}}-\frac {3 a b \left (A b +B a \right )}{7 x^{7}}-\frac {b^{2} \left (A b +3 B a \right )}{6 x^{6}}-\frac {b^{3} B}{5 x^{5}}\) | \(66\) |
norman | \(\frac {-\frac {b^{3} B \,x^{4}}{5}+\left (-\frac {1}{6} b^{3} A -\frac {1}{2} a \,b^{2} B \right ) x^{3}+\left (-\frac {3}{7} a \,b^{2} A -\frac {3}{7} a^{2} b B \right ) x^{2}+\left (-\frac {3}{8} a^{2} b A -\frac {1}{8} a^{3} B \right ) x -\frac {a^{3} A}{9}}{x^{9}}\) | \(74\) |
risch | \(\frac {-\frac {b^{3} B \,x^{4}}{5}+\left (-\frac {1}{6} b^{3} A -\frac {1}{2} a \,b^{2} B \right ) x^{3}+\left (-\frac {3}{7} a \,b^{2} A -\frac {3}{7} a^{2} b B \right ) x^{2}+\left (-\frac {3}{8} a^{2} b A -\frac {1}{8} a^{3} B \right ) x -\frac {a^{3} A}{9}}{x^{9}}\) | \(74\) |
gosper | \(-\frac {504 b^{3} B \,x^{4}+420 A \,b^{3} x^{3}+1260 B a \,b^{2} x^{3}+1080 a A \,b^{2} x^{2}+1080 B \,a^{2} b \,x^{2}+945 a^{2} A b x +315 a^{3} B x +280 a^{3} A}{2520 x^{9}}\) | \(76\) |
parallelrisch | \(-\frac {504 b^{3} B \,x^{4}+420 A \,b^{3} x^{3}+1260 B a \,b^{2} x^{3}+1080 a A \,b^{2} x^{2}+1080 B \,a^{2} b \,x^{2}+945 a^{2} A b x +315 a^{3} B x +280 a^{3} A}{2520 x^{9}}\) | \(76\) |
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Time = 0.21 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {504 \, B b^{3} x^{4} + 280 \, A a^{3} + 420 \, {\left (3 \, B a b^{2} + A b^{3}\right )} x^{3} + 1080 \, {\left (B a^{2} b + A a b^{2}\right )} x^{2} + 315 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x}{2520 \, x^{9}} \]
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Time = 2.08 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.09 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=\frac {- 280 A a^{3} - 504 B b^{3} x^{4} + x^{3} \left (- 420 A b^{3} - 1260 B a b^{2}\right ) + x^{2} \left (- 1080 A a b^{2} - 1080 B a^{2} b\right ) + x \left (- 945 A a^{2} b - 315 B a^{3}\right )}{2520 x^{9}} \]
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Time = 0.21 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.97 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {504 \, B b^{3} x^{4} + 280 \, A a^{3} + 420 \, {\left (3 \, B a b^{2} + A b^{3}\right )} x^{3} + 1080 \, {\left (B a^{2} b + A a b^{2}\right )} x^{2} + 315 \, {\left (B a^{3} + 3 \, A a^{2} b\right )} x}{2520 \, x^{9}} \]
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Time = 0.29 (sec) , antiderivative size = 75, normalized size of antiderivative = 1.00 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {504 \, B b^{3} x^{4} + 1260 \, B a b^{2} x^{3} + 420 \, A b^{3} x^{3} + 1080 \, B a^{2} b x^{2} + 1080 \, A a b^{2} x^{2} + 315 \, B a^{3} x + 945 \, A a^{2} b x + 280 \, A a^{3}}{2520 \, x^{9}} \]
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Time = 0.05 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.99 \[ \int \frac {(a+b x)^3 (A+B x)}{x^{10}} \, dx=-\frac {x^2\,\left (\frac {3\,B\,a^2\,b}{7}+\frac {3\,A\,a\,b^2}{7}\right )+x\,\left (\frac {B\,a^3}{8}+\frac {3\,A\,b\,a^2}{8}\right )+\frac {A\,a^3}{9}+x^3\,\left (\frac {A\,b^3}{6}+\frac {B\,a\,b^2}{2}\right )+\frac {B\,b^3\,x^4}{5}}{x^9} \]
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